
- BYJU'S Online learning Programs For K3, K10, K12, NEET, JEE, UPSC ...- A commutator is a rotatory electrical switch that reverses the direction of current between the rotor and the external circuit periodically. The reversal of the current each half-turn gives rise to a … 
- How to show that the commutator subgroup is a normal subgroup- The commutator subgroup is generated by commutators. Show that the property of "being a commutator" is invariant under conjuation (in fact it is invariant under all automorphisms). 
- The commutator of two matrices - Mathematics Stack Exchange- The commutator [X, Y] of two matrices is defined by the equation $$\begin {align} [X, Y] = XY − YX. \end {align}$$ Two anti-commuting matrices A and B satisfy $$\begin {align} A^2=I \qu... 
- What is a commutator - Mathematics Stack Exchange- The second way is to look at the commutator subgroup as a measure of how noncommutative a group is. A group is commutative if it has a trivial commutator subgroup (and highly … 
- What is the function of commutator? Physics Q&A - BYJU'S- The function of a commutator. The commutator ring of an electric motor reverses the direction of current flowing through the coil every time the coil barely reaches the vertical position during a … 
- Dot products in commutators - Mathematics Stack Exchange- What does the commutator $ [\hat p, \vec c\cdot\hat r]$ mean? I see that you can expand the second term such that the commutator becomes $ [\hat p, c_xr_x+c_yr_y+c_zr_z]$ but then … 
- Understanding the commutator subgroup of the dihedral group- @NizarHalloun: Terminology issue: A "commutator" is an element of a group. You are talking about the "commutator subgroup," which is the subgroup generated by commutators. 
- Why is the commutator defined differently for groups and rings?- Jun 30, 2015 · The commutator of a group and a commutator of a ring, though similar, are fundamentally different, as you say. In each case, however, the commutator measures the … 
- Calculating the commutator (derived) subgroup of $S_3$- If $x$ and $y$ are in $S_3$, then their commutator, $x^ {-1}y^ {-1}xy$, is an even permutation. So the commutator subgroup is a subgroup of $A_3$, which is just the identity and the 3-cycles. 
- Commutator relationship proof $ [A,B^2] = 2B [A,B]$- Oct 7, 2012 · These are supposed to be quantum mechanics operators. Well, I was hoping to show algebraically that [A,B] must necessarily be something like a constant.