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  1. BYJU'S Online learning Programs For K3, K10, K12, NEET, JEE, UPSC ...

    A commutator is a rotatory electrical switch that reverses the direction of current between the rotor and the external circuit periodically. The reversal of the current each half-turn gives rise to a …

  2. How to show that the commutator subgroup is a normal subgroup

    The commutator subgroup is generated by commutators. Show that the property of "being a commutator" is invariant under conjuation (in fact it is invariant under all automorphisms).

  3. The commutator of two matrices - Mathematics Stack Exchange

    The commutator [X, Y] of two matrices is defined by the equation $$\begin {align} [X, Y] = XY − YX. \end {align}$$ Two anti-commuting matrices A and B satisfy $$\begin {align} A^2=I \qu...

  4. What is a commutator - Mathematics Stack Exchange

    The second way is to look at the commutator subgroup as a measure of how noncommutative a group is. A group is commutative if it has a trivial commutator subgroup (and highly …

  5. What is the function of commutator? Physics Q&A - BYJU'S

    The function of a commutator. The commutator ring of an electric motor reverses the direction of current flowing through the coil every time the coil barely reaches the vertical position during a …

  6. Dot products in commutators - Mathematics Stack Exchange

    What does the commutator $ [\hat p, \vec c\cdot\hat r]$ mean? I see that you can expand the second term such that the commutator becomes $ [\hat p, c_xr_x+c_yr_y+c_zr_z]$ but then …

  7. Understanding the commutator subgroup of the dihedral group

    @NizarHalloun: Terminology issue: A "commutator" is an element of a group. You are talking about the "commutator subgroup," which is the subgroup generated by commutators.

  8. Why is the commutator defined differently for groups and rings?

    Jun 30, 2015 · The commutator of a group and a commutator of a ring, though similar, are fundamentally different, as you say. In each case, however, the commutator measures the …

  9. Calculating the commutator (derived) subgroup of $S_3$

    If $x$ and $y$ are in $S_3$, then their commutator, $x^ {-1}y^ {-1}xy$, is an even permutation. So the commutator subgroup is a subgroup of $A_3$, which is just the identity and the 3-cycles.

  10. Commutator relationship proof $ [A,B^2] = 2B [A,B]$

    Oct 7, 2012 · These are supposed to be quantum mechanics operators. Well, I was hoping to show algebraically that [A,B] must necessarily be something like a constant.