y' (x) = color (blue) (-csc (5x)csc^2x - 5cotxcot (5x)csc (5x) We're asked to find the derivative (dy)/ (dx) [y = (cotx)/ (sin (5x))] We can first use the quotient ...

Explanation: From the given equation #f (x)=csc x- sin x# We determine #f'' (x)#, the second derivative of #f (x)#

The first half is quite easy, just bring the 4 to the front and change the power to 3. # (dy)/ (dx)=4 (csc (6sqrt (x)))^3*f' (x)# The derivative of #csc (g (x))=-g' (x)csc (g (x))cot (g (x))# Here, #g …

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What is the derivative of #csc^2 (x)#? An elevator traveled in this way: up 18 floors, down 6 floors, down 14 floors, up 19 floors and down 25 floors. What was the net change in the position of …

However, we cannot differentiate a non implicit function of #y# wrt #x#. But if we apply the chain rule we can differentiate a function of #y# wrt #y# but we must also multiply the result by #dy/dx#.

The third one is dy/dx = (2x)/(3y^2) and the value is 1/3 So from y^3 - x^2 = 4 We take the derivative as normal d/dx(y^3) - d/dx(x^2) = d/dx(4) d/dx(y^3) - 2x = 0 d/dx(y^3) = 2x Using the …

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How doyou find the derivative of #2sinxcosx#? Why do plant cells that transport water against the force of gravity contain many more mitochondria than other plant cells do? What is the limit of …